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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Motion in One Dimension
Module - 1 Introduction
Duration: 13.56 Min
 
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Duration: 5.23 Min
 
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Duration: 2.26 Min
 
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Duration: 2.33 Min
 
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Module - 5 Acceleration
Duration: 10.41 Min
 
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Duration: 3.38 Min
 
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Duration: 3.51 Min
 
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Duration: 4.12 Min
 
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Duration: 11.18 Min
 
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Module - 10 Solved Example-6
Duration: 3.11 Min
 
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Module - 11 Solved Example-7
Duration: 4.41 Min
 
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Module - 12 Solved Example-8
Duration: 2.29 Min
 
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Module - 13 Solved Example-9
Duration: 2.24 Min
 
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Module - 14 Free Fall Motion
Duration: 6.03 Min
 
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Duration: 2.25 Min
 
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Duration: 10.24 Min
 
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Duration: 3.38 Min
 
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Duration: 5.01 Min
 
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Duration: 17.11 Min
 
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Duration: 14.05 Min
 
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Duration: 13.43 Min
 
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Duration: 5.25 Min
 
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  1.  
  2. sir but if iam doing by the nth second displacement that is by distance = sn-sn-1 in this case= s9-s8 = 2 m/s but sir ur ans is coming 1/2 m/s and when i do the same way as u it is coming 1 /2 m/s
    4 years ago by

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  3.  
  4. Very good teaching sir
    6 years ago by Aditya Pathak

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  5.  
  6. sir could you please explain last part again clearly
    6 years ago by SRI RISHITHA

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  7.  
  8. sir in the last part of video you said the time taken to reach from position at 8 sec to position at 8.5 is same as the time taken to reach back again from 8.5 sec to 8 sec . BUT how this is possible as in 1st case velocity of both are acting in opposite direction whereas in second case accerlation was acting only in one direction so it should reach slightly away from the position at 8th second
    7 years ago by rahul jain

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  9.  
  10. Sir how do we know that particle undergoes a backward motion?
    7 years ago by PRACHI DEV

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  11.  
  12. Sir but the velocity is not acting in the backward journey so how will it take 0.5s to reach back where it was at t=8s
    7 years ago by Rajeev Gupta

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